Suppose in large City A that the average number of homicides is 98 per year, with a standard deviation of 25. In midsized City B, the average number of homicides is 44, with a standard deviation of 17 In 2012, City A had 119 homicides, while City B recorded 62 homicides. Assuming both distributions are normal, calculate the following using the Table A in Appendix C:
1. Which city had the worst number of homicides in 2012 (relative to its norm)?
2. Compute the percentile rank of City A's 2012 homicides.
3. Compute the percentile rank of City B's 2012 homicides.
4. If City B had 33 homicides in 2010, what percentage greater were the homicides in 2012?
1. Z-score of City A = 0.84
Z-score of City B = 1.06
City B was worse in 2012
2. .2995 + .5000 = .7995 = 79.95%
3. .3554 + .5000 = .8554 = 85.54%
4. .2422 + .3554 = .5976 = 59.76% greater
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