Solve the problem.Suppose that the acceleration of an object is given by a(t) = 5t2/3 + 2e-t. The object's initial velocity, v(0), is 12 and the object's initial position, s(0), is -1. Find s(t).
A. s(t) = 3t5/3 - 2e-t + 14
B. s(t) = 
+ 2e-t + 14t - 3
C. s(t) = 
+ 2e-t + 10t - 3
D. s(t) = 
+ 2e-t + 12t - 1
Answer: D
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A. (0, -6) B. (0, -5) C. (-1, -5) D. No solution
Solve the equation.
- 
= 
A. {3}
B. 
C. 
D. no solution
Determine the phase shift of the function.y = 3 cos 
A. 
units to the left
B. 
units to the right
C. 
units to the left
D. 
units to the right
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