Solve the initial value problem.= (4t + 3) sin (2t2 + 3t), s(0) = -6

A. s = cos (2t2 + 3t) - 7
B. s = sin (2t2 + 3t) - 6
C. s = -cos (2t2 + 3t) - 5
D. s = -cos - 

Answer: C

Mathematics

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