If a system has an average power level of 100, an average noise level of 33.33, and a bandwidth of 100 MHz, what is the effective limit on channel capacity?

Question

What will be an ideal response?

Answer 1

Shannon theorem specifies the maximum data rate that could be achieved over a
transmission system that experiences noise:
C = B log 2 (1 + S/N)
where C is the effective limit on the channel capacity in bits per second, B is the bandwidth, and S/N is
the signal-to-noise ratio.
Using the formulae, we can calculate C for the above given values: C = 100,000,000 * log 2 (1 +
100/33.33) = 100,000,000 * log 2 4 = 200,000,000 = 200 Mbps