Find the particular solution for the initial value problem.  = 4xe2x; y(0) = 23

A. y = 4xe2x - 2e2x + 25
B. y = 2xe2x + 23
C. y = 4xe2x - e2x + 24
D. y = 2xe2x - e2x + 24


Answer: D

Mathematics

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