For two benchmarks, x and y, show that their arithmetic mean is always higher than, or the same as, the geometric mean.
What will be an ideal response?
We need to demonstrate that (x + y)/2 ? (x?y) ½
If we multiply by 2, we get (x + y) ? 2(x.y) ½
If we square both sides we get x2 + y2 + 2x?y ? 4x?y or x2 + y2 ? 2x?y or x2 + y2 ? 2x?y ? 0.
We can write (x ? y)2 ? 0
This is clearly true. If x = y, (x ? y)2 = 0 and the arithmetic mean and geometric means are equal. If x and y are
not equal, the value of x ? y is not zero and (x ? y)2 is positive. Therefore, the arithmetic mean is higher than or
the same as the geometric mean.
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A JavaFX event handler for event type T is an instance of _______.
a. ActionEvent
b. Action
c. EventHandler
d. EventHandler
Describe the two tabs on the NFS Client Configuration window.
What will be an ideal response?
In the accompanying figure, item 1 points to the ____.
A. name of the figure B. name of the window C. default document name D. Applications bar