Using the average end area method, determine the required volume of the cuts and fills for a new road. The cuts and fills for each station are shown in Table 9.2. Express your answer in cubic yards.

Question

What will be an ideal response?

Answer 1

The cuts and fills are calculated as follows:

Cut8 + 30 to 8 + 50 = (0 sf + 125 sf) / 2 × 20? = 1,250 bcf / 27 cf per cy = 46 bcy

Cut8 + 50 to 9 + 00 = (125 sf + 168 sf) / 2 × 50? = 7,325 bcf / 27 cf per cy = 271 bcy

Cut9 + 00 to 9 + 50 = (168 sf + 210 sf) / 2 × 50? = 9,450 bcf / 27 cf per cy = 350 bcy

Cut9 + 50 to 10 + 00 = (210 sf + 144 sf) / 2 × 50? = 8,850 bcf / 27 cf per cy = 328 bcy

Cut10 + 00 to 10 + 50 = (144 sf + 75 sf) / 2 × 50? = 5,475 bcf / 27 cf per cy = 203 bcy

Cut10 + 50 to 10 + 75 = (75 sf + 0 sf) / 2 × 25? = 938 bcf / 27 cf per cy = 35 bcy

Total Cuts = 46 bcy + 271 bcy + 350 bcy + 328 bcy + 203 bcy + 35 bcy = 1,233 bcy

Fill8 + 30 to 8 + 50 = (0 sf + 25 sf) / 2 × 20? = 250 ccf / 27 cf per cy = 9 ccy

Fill8 + 50 to 9 + 00 = (25 sf + 0 sf) / 2 × 50? = 625 ccf / 27 cf per cy = 23 ccy

Fill9 + 00 to 9 + 50 = (0 sf + 0 sf) / 2 × 50? = 0 ccf / 27 cf per cy = 0 ccy

Fill9 + 50 to 10 + 00 = (0 sf + 95 sf) / 2 × 50? = 2,375 ccf / 27 cf per cy = 88 ccy

Fill10 + 00 to 10 + 50 = (95 sf + 65 sf) / 2 × 50? = 4,000 ccf / 27 cf per cy = 148 ccy

Fill10 + 50 to 10 + 75 = (65 sf + 0 sf) / 2 × 25? = 812 ccf / 27 cf per cy = 30 ccy

Total Fills = 9 ccy + 23 ccy + 0 ccy + 88 ccy + 148 ccy + 30 ccy = 298 ccy