Solve the initial value problem for x as a function of t.(2t3 - 2t2 + t - 1)  = 3, x(2) = 0

A. x = ln   -  tan-1  t +  tan-1 2 
B. x = ln   - tan-1  t - ln  + tan-1 2 + ln 4.5
C. x = ln   -  tan-1  t -  ln  +  tan-1 2 +  ln 4.5
D. x = ln  -  ln  +  ln 4.5


Answer: C

Mathematics

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