Solve the initial value problem for x as a function of t.(2t3 - 2t2 + t - 1)
= 3, x(2) = 0
A. x = ln -
tan-1
t +
tan-1 2
B. x = ln - tan-1
t - ln
+ tan-1 2
+ ln 4.5
C. x = ln -
tan-1
t -
ln
+
tan-1 2
+
ln 4.5
D. x = ln -
ln
+
ln 4.5
Answer: C
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