Find the value of a so that the trigonometric function passes through the given point.y = a cos x(2?, 2)
A. 2?
B. -2
C. 1
D. 2
Answer: D
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Name the conic or limiting form represented by the given equation.4x2 + 48x + 144 = 0
A. Point B. Parabola C. Line D. Ellipse
Identify the base and the exponent. Do not evaluate.-9.75
A. Base: 5, exponent: -9.7 B. Base: 9.7, exponent: 5 C. Base: -9.7, exponent: 5 D. Base: 5, exponent: 9.7
Rotate the axes so that the new equation contains no xy-term. Discuss the new equation.x2 + xy + y2 - 3y - 6 = 0
A. ? = 45° +
= 1
ellipse
center at (0, 0)
major axis is y'-axis
vertices at (0, ±2)
B. ? = 45° +
= 1
ellipse
center at (,
)
major axis is y'-axis
vertices at (, -
) and (
,
)
C. ? = 45°
y'2 = -18x'
parabola
vertex at (0, 0)
focus at (- , 0)
D. ? = 45° -
= 1
hyperbola
center at (0, 0)
transverse axis is the x'-axis
vertices at (±, 0)
Decide whether or not the ordered pair is a solution of the system.(5, 5)3x + y = 104x + 3y = 5
A. Yes B. No