Find an equation of the tangent line to the graph of y = x3 ln(-2x) at x = -1.
A. y = (x + ln 2) - 1
B. y = (1 + 3 ln 2)(x + 1) - ln 2
C. y + ln 2 = 4(x - 1)
D. y - 1 = 4(x - ln 2)
Answer: B
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