sum and item are initialized to 0 before the loop. In the loop, item++ increments item by 1 and item is then added to sum. If sum > 4, the break statement exits the loop. item is initially 0, then 1, 2, 3 and sum is initially 0, and then 1, 3, and 6. When sum is 6, (sum > 4) is true, which causes the break statement to be executed. So, the correct answer is B.

Question

```
int number = 25;
int i;

boolean isPrime = true;
for (i = 2; i < number && isPrime; i++) {
if (number % i == 0) {
isPrime = false;
}
}
System.out.println("i is " + i + " isPrime is " + isPrime);
```
a. i is 5 isPrime is true
b. i is 5 isPrime is false
c. i is 6 isPrime is true
d. i is 6 isPrime is false

Answer 1

d. i is 6 isPrime is false
The code tests if number is prime by dividing the number with possible divisors 2, 3, 4, and so on. Initially, isPrime is set to true. Once a divisor is found (i.e., number % i == 0 is true), isPrime is set to false. The loop continuation condition now becomes false. The loop ends. If no divisor is found after the loop is finished, isPrime remains true. Since number is 25, number % i == 0 is true when i is 5. In this case, isPrime is set to false and i++ increments i by 1 in the action-after-each-iteration. So, the output is that i is 6 and isPrime is false. The correct anwer is D.