Solve the problem.A rotating beacon is located 11 ft from a wall. If the distance from the beacon to the point on the wall where the beacon is aimed is given by a = 11|sec 2?t|,where t is in seconds, find a when t = 0.41 seconds. Round your answer to the nearest hundredth.
A. -13.03 ft
B. 39.43 ft
C. 26.23 ft
D. 13.03 ft
Answer: D
Mathematics
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, 
, 
, and 
.
A. 
B. 
C. e - 1
D. 2e - 1
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A. (10km - 4m2)(25k2 + 4m2) B. 2m(5k + 2m2)(25k2 - 10km + 4km2) C. 2m(125k - 2m)(k2 + 10km + 4m2) D. 2m(5k - 2m)(25k2 + 10km + 4m2)
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