Hydrolysis reactions are commonly used inside the cell to split high-energy covalent bonds. For each of the three reactions below, use the ?G° for each reaction to determine the equilibrium constants (K)
Assume that each reaction occurs independently of the other two.
?G° (kcal/mole)
Reaction 1: acetyl-P -> actetate + P –10.3
Reaction 2: ATP -> ADP + P –7.3
Reaction 3: glucose6-P -> glucose + P –3.3
K can be easily calculated from the standard free-energy values by solving the standard free-energy equation (ΔG° = –1.42 log K)for K (K =10ΔG°/–1.42).
Reaction 1: K = 107.25
Reaction 2: K = 105.14
Reaction 3: K = 102.32
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