Determine the total energy of water vapor with a mass of 2.50 kg, a specific internal energy of 2780 kJ/kg, traveling at a velocity of 56.0 m/s at a height of 3.50 m.
Given: m = 2.50 kg ; z = 3.50 m; V = 56.0 m/s; u = 2780 kJ/kg
Assume: g = 9.81 m/s2
What will be an ideal response?
E = mu + ½ mV2 + mgz
= (2.50 kg)[2780 kJ/kg + ½ (56.0 m/s)2/(1000 J/kJ) + (9.81 m/s2)(3.50 m)/(1000 J/kJ)]
E = 6950 kJ (6954 kJ)
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