The genes for mahogany eyes and ebony body are approximately 25 map units apart on chromosome III in Drosophila
Assume that a mahogany-eyed female was mated to an ebony-bodied male and that the resulting F1 phenotypically wild-type females were mated to mahogany, ebony males. Of 1000 offspring, what would be the expected phenotypes, and in what numbers would they be expected?
mahogany = 375; ebony = 375; wild-type = 125; mahogany-ebony = 125
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Diatoms
A. can reproduce asexually. B. are photosynthetic with frustules composed of two halves. C. are motile by virtue of having flagella. D. are photosynthetic with frustules composed of two halves and can reproduce asexually.
The grouping or classification of species is termed
A. eukaryotism. B. prokaryotism. C. genus. D. kingdom. E. taxonomy.
In DNA, the substitution of a purine for a pyrimidine or a pyrimidine for a purine is called a(n) ________
A) inversion B) transmutation C) transversion D) transition E) substitution
Which statement about cell adhesion molecules (CAMs) is false?
A) They are glycoproteins. B) They bind to CAMs on other cells. C) They are all produced by the same gene. D) They contribute to cell migration. E) They contribute to stable tissue structure.