Solve.Find the center, vertices, foci, and asymptotes of the hyperbola x2 - 4y2 - 6x + 16y - 11 = 0
A. center at (2, 3)
vertices at (0, 3) and (4, 3)
foci at (2 - 
, 3) and (2 + 
, 3)
asymptotes of y - 3 = - 
(x - 2) and y - 3 = 
(x - 2)
B. center at (3, 2)
vertices at (2, 2) and (4, 2)
foci at (3 - 
, 2) and (3 + 
, 2)
asymptotes of y - 2 = - 2(x - 3) and y - 2 = 2(x - 3)
C. center at (3, 2)
vertices at (1, 2) and (5, 2)
foci at (3 - 
, 2) and (3 + 
, 2)
asymptotes of y - 2 = - 
(x - 3) and y - 2 = 
(x - 3)
D. center at (3, 2)
vertices at (3, 0) and (3, 4)
foci at (3, 2 - 
) and (3, 2 + 
)
asymptotes of y + 2 = - 2(x + 3) and y + 2 = 2(x + 3)
Answer: C
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