Solve the problem.The current (in amperes) in an inductor of inductance L (in henries) is given by 
where V is the voltage (in volts) and t is the time (in seconds). Find a formula for i, if 
A. i = L
+ C
B. i = 
+ C
C. i = 
+ C
D. i = L
+ C
Answer: C
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Solve.A resistor and inductor are connected in series to a battery. The current in the circuit (in A) is given by 
where t is the time since the circuit was closed. Find the first three terms of the Maclauren expansion of this function.
A. 0.12t - 0.06t2 + 0.02t3 + . . . B. 1.2t + 0.006t2 + 0.0002t3 + . . . C. 0.12t - 0.006t2 + 0.0002t3 + . . . D. 0.12t - 0.006t2 + 0.0004t3 + . . .
Use ordinary division of polynomials to find the quotient and remainder when the first polynomial is divided by the second.x4 - 2x3 + 3x2 - 2x + 2, x2 + 1
A. x2 + 2x + 2 B. x2 - 2x + 2; -2x - 2 C. x2 + 2x + 2; -2x - 2 D. x2 - 2x + 2
For the equation, create a table, -3 ? x ? 3, and list points on the graph.y = x2 + 2
A. 
(-3, -1), (-2, 0), (-1, 1), (0, 2), (1, 3), (2, 4), (3, 5)
B. 
(-3, 10), (-2, 5), (-1, 2), (0, 1), (1, 2), (2, 5), (3, 10)
C. 
(-3, 11), (-2, 6), (-1, 3), (0, 2), (1, 3), (2, 6), (3, 11)
D. 
(-3, 7), (-2, 2), (-1, -1), (0, -2), (1, -1), (2, 2), (3, 7)
Find all solutions if 
. Round your answer to the nearest tenth.
?
?
A. 27.6°, 92.4°, 151.3°, 218.2°, 267.6°, 324.6° B. 28.8°, 90.3°, 147.6°, 212.4°, 270.8°, 332.4° C. 27.6°, 92.4°, 147.6°, 212.4°, 267.6°, 332.4 D. 27.6°, 90.3°, 151.3°, 212.4°, 267.6°, 332.4° E. 28.8°, 92.4°, 147.6°, 218.2°, 270.8°, 332.4°