Solve the problem.A trust account manager has $300,000 to be invested in three different accounts. The accounts pay 5%, 6%, and 8%, and the goal is to earn $18,000. Assuming that x dollars are invested at 5%, y dollars are invested at 6%, and z dollars are invested at 8%, find x in terms of z.
A. x = z
B. x = 300,000 - 3z
C. x = 100,000 + z
D. x = 2z
Answer: D
Mathematics
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Mathematics