Find four consecutive integers that sum to 34.

Let smallest number = n
Four consecutive numbers are: n, (n + 1), (n + 2), and (n + 3)
Equation: n + (n + 1) + (n + 2) + (n + 3) = 34
Solve for n: 4n + 6 = 34
4n=34-6 n=28/4
n = 7


Solution: The four consecutive numbers are: 7, 8, 9, and 10.
Check: 7 + 8 + 9 + 10 = 34 Solution checks

Computer Science & Information Technology

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