Find three consecutive integers in which the sum of the first two is 27 more than the third.
Let smallest number = n
Three consecutive numbers are: n, (n + 1), and (n + 2)
Equation: n + (n + 1) = 27 + (n + 2)
Solve for n: 2n + 1 = 29 + n
2n — n = 29 —1 n =28
Solution: The three numbers are: 28, 29, and 30.
Check: 28+ 29=27+ 30
57 = 57
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