Find the standard form of the equation of the hyperbola satisfying the given conditions.Center: (6, 3); Focus: (4, 3); Vertex: (5, 3)

A. (x - 3)2 -  = 1
B.  - (y - 6)2 = 1
C.  - (y - 3)2 = 1
D. (x - 6)2 -  = 1

Answer: D

Mathematics

You might also like to view...

Find the equation in standard form of an ellipse centered at the origin that passes through the given points.(-7, 0), (7, 0), (0, -4), and (0, 4)

A. 49x2 + 16y2 = 1
B.  +  = 1
C.  +  = 1
D.  +  = 1

View
Mathematics

Find Y and é in the parallel circuit below if BC = 400 æS and G = 250 æS.



a. é = 60ø, Y = 500 æS
b. é = 30ø, Y = 289 æS
c. é = 60ø, Y = 800 æS
d. é = 30ø, Y = 800 æS
e. é = 58ø, Y = 472 æS

View
Mathematics

Use integration by parts to find the integral. Round the answer to two decimal places if necessary.

A. 26.1 B. 20.11 C. 6.70 D. 4.74

View
Mathematics

Solve for the specified variable.S = 2?rh + 2?r2  for h

A. h = S - r
B. h =  - 1
C. h = 
D. h = 2?(S - r)

View
Mathematics