In the circuit shown below, let





Use mesh analysis to find mesh currents I1, I2, and I3. Also, find V1, V2, and V3.










Vs=5;Is=0.002;

R1=1000;R2=400;R3=1500;R4=2000;R5=500;

syms I1 I2 I3

[I1,I2,I3]=solve(-Vs+R1*I1+R2*(I1-I2)+R5*(I1-I3),...

R2*(I2-I1)+R4*I2+R3*(I2-I3),...

I3==-Is,I1,I2,I3)

V2=R5*(I1-I3)

V1=V2+R2*(I1-I2)

V3=V1-R4*I2

IR4=-I2

IR1=I1

IR2=I1-I2

IR3=I2-I3

IR5=I1-I3

SumI=-IR2-IR3+IR5

I1=vpa(I1,7)

I2=vpa(I2,7)

I3=vpa(I3,7)

V1=vpa(V1,7)

V2=vpa(V2,7)

V3=vpa(V3,7)

IR4=vpa(IR4,7)

IR1=vpa(IR1,7)

IR2=vpa(IR2,7)

IR3=vpa(IR3,7)

IR5=vpa(IR5,7)

SumI=vpa(SumI,7)

Answers:

I1 =

0.001986207

I2 =

-0.0005655172

I3 =

-0.002

V1 =

3.013793

V2 =

1.993103

V3 =

4.144828

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