Solve the given differential equation.
+ y = 14 + 6 cos 3x
A. y = c1 sin x + c2 cos x + 
cos 3x + 14
B. y = c1 sin x + c2 cos x - 
cos 3x
C. y = c1 sin x + c2 cos x - 
sin 3x + 14
D. y = c1 sin x + c2 cos x - 
cos 3x + 14
Answer: D
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