Solve the problem.A Ferris wheel has a diameter of 380 feet and the bottom of the Ferris wheel is 10 feet above the ground. Find the equation of the wheel if the origin is placed on the ground directly below the center of the wheel, as illustrated. 
A. x2 + (y - 200)2 = 36,100
B. x2 + y2 = 36,100
C. x2 + (y - 190)2 = 36,100
D. x2 + (y - 190)2 = 144,400
Answer: A
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Solve.The current in a circuit changes from -6 amperes to 4 amperes. What is the change in current?
Fill in the blank(s) with the appropriate word(s).
Write the function in the form y = f(u) and u = g(x). Then find dy/dx as a function of x.y = csc(cot x)
A. y = csc u; u = cot x; 
= csc3 x cot x
B. y = cot u; u = csc x; 
= csc2(csc x) csc x cot x
C. y = csc u; u = cot x; 
= - csc(cot x) cot(cot x)
D. y = csc u; u = cot x; 
= csc(cot x) cot(cot x) csc2 x
Find an equation for the line, in the indicated form, with the given properties. Containing the points (2, 0) and (-7, -5); general form
A. -5x + 9y = -10 B. -2x + 2y = 24 C. 5x + 9y = -10 D. 2x - 2y = 24
Solve.While traveling in a car, the centrifugal force a passenger experiences as the car drives in a circle varies jointly as the mass of the passenger and the square of the speed of the car. If the a passenger experiences a force of 90 newtons when the car is moving at a speed of 50 kilometers per hour and the passenger has a mass of 40 kilograms, find the force a passenger experiences when the car is moving at 30 kilometers per hour and the passenger has a mass of 90 kilograms.
A. 90 newtons B. 64.8 newtons C. 81 newtons D. 72.9 newtons