Now, for problem 2.9 replace the steam with liquid water. If the specific internal energy of the liquid water is 120 kJ/kg, determine the total internal energy, the kinetic energy, and the potential energy of 1.50 kg of water in the pipe.

Given: m = 1.50 kg; z = 4 m; V = 80.0 m/s; u = 120 kJ/kg
Assume: g = 9.81 m/s2

What will be an ideal response?


U = mu = (1.50 kg) (120 kJ/kg) = 180 kJ
KE = ½ mV2 = ½ (1.50 kg)(80.0 m/s)2 = 4,800 J = 4.80 kJ
PE = mgz = (1.50 kg)(9.81 m/s2)(4 m) = 58.9 J = 0.0589 kJ

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