Solve the linear inequality. Graph the solution set on a number line, and express the solution using interval notation.5x - 2 > 4x - 7
A. (-9, ?)
B. (-?, -5]
C. (-5, ?)
D. [-5, ?)
Answer: C
You might also like to view...
Solve the problem.The liquid portion of a diet is to provide at least 300 calories, 36 units of vitamin A, and 90 units of vitamin C daily. A cup of dietary drink X provides 60 calories, 12 units of vitamin A, and 10 units of vitamin C. A cup of dietary drink Y provides 60 calories, 6 units of vitamin A, and 30 units of vitamin C. Set up a system of linear inequalities that describes the minimum daily requirements for calories and vitamins. Let x = number of cups of dietary drink X, and y = number of cups of dietary drink Y. Write all the constraints as a system of linear inequalities.
A. 60x + 60y > 300 12x + 6y > 36 10x + 30y > 90 x > 0 y > 0 B. 60x + 60y ? 300 12x + 6y ? 36 10x + 30y ? 90 x ? 0 y ? 0 C. 60x + 60y ? 300 12x + 6y > 36 10x + 30y ? 90 D. 60x + 60y ? 300 12x + 6y ? 36 10x + 30y ? 90 x ? 0 y ? 0
Write the number in standard form.1.41 × 10-4
A. -141,000 B. 0.00141 C. 0.0000141 D. 0.000141
Solve the problem.The table lists the average monthly temperatures of two cities for January through June of last year.
Find Central's median temperature for this time period and Naborly's median temperature for this time period. How much warmer is Naborly than Central? Round answers to the nearest whole degree.
A. Central: 48 Naborly: 56 8 degrees warmer B. Central: 55 Naborly: 48 7 degrees warmer C. Central: 48 Naborly: 70 22 degrees warmer D. Central: 48 Naborly: 55 7 degrees warmer
Provide an appropriate response.Given that A(x) = C(x)/x , where A(x) is the average-cost function and C(x) is the total-cost function, find an expression for A'(x) and solve the equation A'(x) = 0 to find the minimum average cost.
A. A'(x) = 
= 0 ? xC(x) - C'(x) = 0 ? 
= A(x) = 
B. A'(x) = 
= 0 ? xC(x) - C'(x) = 0 ? 
= A(x) = 
C. A'(x) = 
= 0 ? xC(x) - C'(x) = 0 ? 
= A(x) = C(x)
D. A'(x) = 
= 0 ? xC'(x) - C(x) = 0 ? 
= A(x) = C'(x)