Provide an appropriate response.A club has n (n ? 3) members. They want to choose 3 people from among these n members to form a committee. Prove by induction that the number of possible ways of choosing the 3 people is
.
What will be an ideal response?
Answers may vary. Possible answer:
First, we show the statement is true when n = 3.
When n = 3, there is only one way to choose a committee of 3 - all 3 members must be on the committee. When n = 3,
So P3 is true and the first condition for the principle of induction is satisfied.
Next, we assume the statement holds for some unspecified natural number k. That is, we assume that Pk is true:
Pk: the number of ways to choose the committee of 3 from k members is .
On the basis of the assumption that Pk is true, we need to show that Pk+1 is true.
Pk+1: the number of ways to choose the committee of 3 from k + 1 members is .
The number of ways to choose the committee of 3 from k + 1 members is the number of ways to choose the committee from the first k members plus the number of ways to choose the committee such that the committee includes the (k + 1)st member and 2 of the first k members.
Thus, the number of ways to choose the committee of 3 from k + 1 members is +
= +
=
=
=
So Pk+1 is true if Pk is assumed true. Therefore, by the principle of mathematical induction, the number of ways to choose a committee of 3 from n members is .
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A. y = 4x
B. y = x + 15
C. y = x
D. y = x
Simplify, if possible.
A.
B.
C.
D. -1