Suppose the following code is embedded in an otherwise correct and complete program. Answer below the question about what version of f() is called in g().
```
void f(); //global
namespace A
{
void g()
{
f(); //Does this call A::f()? Or the global f()?
}
void f();
}
```
a) The call is to the global f();
b) The call is to the namespace A version of f(), i.e., A::f();
c) There is an error. There is a conflict between the namespace f() and the global f(), so there is no call made at all
d) There are other errors that prevent the code from running.
a) The call is to the global f();
b) A use of a name refers to a global namespace version if not masked by a name defined in the name space prior to the use. The definition of A::f() has not been seen at the point that A::g() is invoked. c) There is no conflict between global namespace names and names defined in other namespaces.
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