Solve the problem.A trust account manager has $500,000 to be invested in three different accounts. The accounts pay 5%, 6%, and 8%, and the goal is to earn $34,000. Assuming that x dollars are invested at 5%, y dollars are invested at 6%, and z dollars are invested at 8%, find y in terms of z.
A. y = -600,000 + 2z
B. y = -400,000 + 2z
C. y = 1,100,000 - 3z
D. y = 900,000 - 3z
Answer: D
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