Solve the problem.A trust account manager has $500,000 to be invested in three different accounts. The accounts pay 5%, 6%, and 8%, and the goal is to earn $34,000. Assuming that x dollars are invested at 5%, y dollars are invested at 6%, and z dollars are invested at 8%, find y in terms of z.
A. y = -600,000 + 2z
B. y = -400,000 + 2z
C. y = 1,100,000 - 3z
D. y = 900,000 - 3z
Answer: D
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Use synthetic division to divide.(x4 - 625) ÷ (x + 5)
A. x3 + 5x2 - 25x + 125 B. x2 + 5x + 25 C. x3 + 5x2 + 25x + 125 D. x3 - 5x2 + 25x - 125
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