Solve the initial value problem.
= 5; y "(0) = 5, y '(0) = 5, y(0) = 5
A. y = 
x3 - 
x2 + 5
B. y = 
x3 + 
x2 + 5x + 5
C. y = 5
D. y = 
x3 + 
x2 + 5x + 5
Answer: D
Mathematics
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