1.5 kg of air is initially at 25°C. The enthalpy of the air is increased by 850 kJ. Considering the variability of the specific heats, determine the final temperature of the air.

Given: m = 1.5 kg; T1 = 25°C; ?H = 850 kJ

What will be an ideal response?


From the air tables or on-line properties, h1 = 298.18 kJ/kg
Then, ?H = m (h2 – h1)
Solving for h2 = 298.18 kJ/kg + (850 kJ)/(1.5 kg) = 864.85 kJ/kg
Interpolating on air tables or on-line properties, yields T2 = 839 K = 566°C for the value of h2.

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