The growth rate G, in hundreds of new cases per day, in the spread of an epidemic depends on the number S, measured in hundreds, of currently sick individuals. The relationship, which is valid for up to 4000 currently sick people (that is, 
), is
.
A: What is the smallest value of S for which the growth rate is 1614 new cases per day (that is, 
)? Round your answer for S to the nearest whole number.B. For S between 0 and 40, what number of currently sick individuals gives the maximum growth rate, and what is that growth rate? Round the growth rate to the nearest whole number, and remember that G is measured in hundreds of new cases per day.C: Explain what is happening at value you found in part B.
What will be an ideal response?
hundred cases?
B. When there are 4,000 currently sick individuals, the maximum growth rate of 8,626 new cases per day occurs.
?
C. There are 8,626 new cases on that day.
You might also like to view...
Determine whether the argument is valid or invalid. You may compare the argument to a common form, if applicable, or use a truth table.If I'm hungry, then I will eat.I'm not hungry. ? I will not eat.
A. Invalid B. Valid
Evaluate the expression for othe given values of the variables.-
for x = -4, and y = 3
A. -22 B. -31 C. -24 D. -27
Use radical notation to rewrite the expression. Simplify, if possible.84/3
A. 16 B. 64 C. 128 D. 32
Solve the problem.The linear equation in two variables y = 116 - 3x models the amount of water, y, in ounces, remaining in a leaky bucket x minutes after the bucket was filled. The equation indicates that the bucket initially contains 116 ounces of water and loses 3 ounces each minute. Find a solution of y = 116 - 3x using 5 for x.
A. (5, 131) B. (5, 15) C. (5, 113) D. (5, 101)