Solve the problem.A standard train ticket in a certain city costs 
per ride. People who use the train also have the option of purchasing a frequent-rider pass for 
each month. With the pass, a ticket costs only
per ride. How many train rides in a month make the frequent-rider pass a better deal than standard train tickets?
A. 20 or more rides
B. 22 or more rides
C. 23 or more rides
D. 21 or more rides
Answer: B
Mathematics
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Factor completely.3y2z - 42yz + 135z
A. (3yz + 5)(y + 9) B. 3z(y + 5)(y + 9) C. 3z(y - 5)(y - 9) D. (yz + 5)(3yz + 27)
Mathematics
Write the decimal in words.5.704
A. five and seventy thousand four hundredths B. five and seven hundred four thousandths C. five and seventy-four thousandths D. five and seventy tenths and four thousandths
Mathematics
Simplify the expression. Write the answer with only positive exponents. All variables are nonzero.
A. 
B. 
C. 2mn2
D. 2m33n12
Mathematics
Solve.?x + 5? - 3 = -1
A. 3, 7 B. -3 C. No solution D. -7, -3
Mathematics