In rabbits, spotted coat (S) is dominant to solid color (s) and black (B) is dominant to brown (b). A true-breeding black spotted rabbit is mated to a true-breeding brown solid rabbit to produce a heterozygous F1 generation. Two F1 individuals are mated, and you do not see a 9:3:3:1 (black spotted: black solid: brown spotted: brown solid) ratio of offspring, but instead see that almost all offspring are a non-recombinant phenotype. This tells you that
A. that the genes for fur pattern (spotted vs. nonspotted) and fur color are on the same chromosome.
B. that the genes for fur pattern (spotted vs. nonspotted) and fur color assort independently.
C. that fur pattern (spotted vs. nonspotted) and fur color are maternally inherited.
D. that the genes for fur pattern (spotted vs. nonspotted) and fur color are on the X-chromosome and Y-chromosome, respectively.
E. that the genes for fur pattern (spotted vs. nonspotted) and fur color are on different chromosomes.
Answer: A
You might also like to view...
Since the whole genome sequencing method eliminates the need for constructing physical and genetic maps, this method is _____
a. superior for linkage studies b. the only sequencing method currently used in genomics research c. faster than the map-based sequencing method d. more accurate than the map-based sequencing method e. less accurate than the map-based sequencing method
Which group uses light energy to break down organic molecules from their environment?
a. eukaryotic photoautotrophs b. bacterial photoautotrophs c. eukaryotic photoheterotrophs d. bacterial photoheterotrophs e. all chemoheterotrophs
Cytotoxic T cells recognize antigens bound to _____ whereas helper T cells recognize antigens bound to _____.
What will be an ideal response?
Insulin promotes the storage of glucose by:
a. stimulating protein synthesis. b. increasing the use of fatty acids as fuel. c. promoting the liver to release glucose. d. stimulating fatty acid release by adipose tissue. e. inhibiting glycogen formation.