Solve using artificial variables.Maximizez = 3x1 + 2x2subject to:x1 + x2 = 5 4x1 + 2x2 ? 12 5x1 + 2x2 ? 16 x1 ? 0, x2 ? 0
A. Maximum is 12 for x1 = 2, x2 = 3
B. Maximum is 14 for x1 = 4, x2 = 1
C. Maximum is 13 for x1 = 3, x2 = 2
D. Maximum is 15 for x1 = 5, x2 = 0
Answer: A
Mathematics
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