The primal problem and the final tableau in the solution of the primal problem are given. Use the final tableau to solve the dual problem.Primal problem:Maximize 3x1 + 4x2 + 2x3subject to x1 + x3 ? 16 2x2 + x3 ? 20 3x1 + 6x2 ? 36and x1 ? 0, x2 ? 0, x3 ? 0Final tableau in solution to primal problem: x1 x2 x3 x4 x5 x6 M 
A. Minimum = 576 when y1 = 4, y2 = 4, and y3 = 12
B. Minimum = 52 when y1 = 
, y2 = 
, and y3 = 
C. Minimum = 
when y1 = 
, y2 = 
, and y3 = 
D. Minimum = 52 when y1 = 4, y2 = 4, and y3 = 12
Answer: B
Mathematics
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x + 
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