If bulk candy costs $4.00 a pound and 1 pound fills a box 5 inches by 3 inches by 2 inches, how much wil

Question

Additional information
The volume of a rectangular box is the product of its three dimensions.
Preliminary calculations
v1 (in3) = 5 (in.) * 3 (in.) * 2 (in.) = 30 (in3)
v2 (in3) = 3 (in.) * 4 (in.) * 5 (in.) = 60 (in3)
Let x equal what you are trying to find x = ($ / box2)
Reciprocal factors
4.00 ($ / lb)
1 (lb / box,) 30 (in3 / boxi) 60 (in3 / box2) 1 /4 (lb / $)
1 (boxi / lb) '
1 / 30 (boxi / in3)
1 / 60 (box2 / in3) From volume v1 above
From-volume v2 above

Answer 1

Build an equation
x ($ / box2) = 4.00 ($ / 413) 1 / * 60 OW / box2) * 1 / 30 (be-xi / in )
Multiply factors
x ($ / box2) = 8.00 ($ / box2) Cost of candy in box2 is $8.00.
Solution by simple reasoning (in this case easier than unit analysis) Cost of box, is $4.00
Box2 will hold twice the candy as box] (60 is twice 30) Cost of box2 is twice $4.00 or $8.00.