Each month, in its elliptical orbit around the earth, the moon ranges from a maximum of about 248,000 miles to a minimum of about 217,000 miles above the surface of the earth. The farther the moon is from the earth, the smaller it appears in the sky. The closer it is, the larger it appears. It is a wonderful accident that somewhere within this range is the precise distance at which the moon
appears exactly the same size the sun. Every few years, when the earth, moon, and sun are aligned in a straight line and the moon is at the correct distance, the moon's shadow sweeps across the face of the earth. This is the spectacle of a total eclipse of the sun.
Given the following information, use proportional right triangles to determine the distance of the moon from the surface of the earth so the disk of the moon will appear in the sky to be the same size as the disk of the sun.
Radius of sun: 435,000 miles
Radius of moon: 1080 miles
Distance from earth to sun: 93,000,000 miles
Solve the following time-rate-distance problems using the IPO method. Ignore time zones.
Output The distance of the moon from the surface of the earth so the disk of the moon will appear in the sky to be the same size as the disk of the sun
Input Radius of sun 435,000 miles
Radius of moon 1080 miles
Distance from earth to sun 93,000,000 miles
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