Simplify by factoring out the given factor.2m7/4 - 5m-1/2; m-1/2
A. m-1/2( 2m9/4 - 5)
B. m-1/2(2m7/4 + 5)
C. m-1/2(10m9/4 - 2)
D. 5 m-1/4(2m9/4 - 1 )
Answer: A
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Solve the problem.A small frictionless cart, attached to the wall by a spring, is pulled 10 cm back from its rest position and released at time t = 0 to roll back and forth for 4 sec. Its position at time t is 
. What is the cart's maximum speed? When is the cart moving that fast? What is the magnitude of of the acceleration then?
A. ? ? 3.14 cm/sec; t = 0.5 sec, 1.5 sec, 2.5 sec, 3.5 sec; acceleration is 0 cm/sec2 B. 10? ? 31.42 cm/sec; t = 0 sec, 1 sec, 2 sec, 3 sec; acceleration is 0 cm/sec2 C. 10? ? 31.42 cm/sec; t = 0.5 sec, 2.5 sec; acceleration is 1 cm/sec2 D. 10? ? 31.42 cm/sec; t = 0.5 sec, 1.5 sec, 2.5 sec, 3.5 sec; acceleration is 0 cm/sec2
Graph the pair of parametric equations with the aid of a graphing calculator.x = 5 tan t, y = 3 sec t; -?/2 ? t ? ?/2 
A. 
B. 
C. 
D. 
Find the equation of the transverse axis of the hyperbola.(y + 2)2 - 25(x + 1)2 = 25
A. y = 0 B. y = 5 C. x = 1 D. x = -1
Give the coefficient and degree of the term.-8x11y9
A. -8, 20 B. 8, 99 C. 8, 20 D. -8, 11