A hydrogen atom initially in the n = 6 state decays to the n = 2 state. The emitted photon is detected in a photographic plate
What is the wavelength of the detected photon? The lowest level energy state of hydrogen is -13.6 eV. (h = 6.626 × 10-34 J ? s, 1 eV = 1.60 × 10-19 J,
c = 3.00 × 108 m/s)
A) 410 nm
B) 93.8 nm
C) 1090 nm
D) 93.1 nm
Answer: A
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