A deck of cards contains 52 cards. These cards consist of four suits - hearts, spades, clubs, and diamonds. Each suit contains one of each of the following: 2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace. Assume that one card is selected at random from a well-shuffled deck of cards.Find the probability that the card is a diamond.
A.
B.
C.
D.
Answer: B
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Find the absolute extreme values of the function on the interval.f(x) = tan x, - ? x ?
A. absolute maximum is at x =
and -
; no minimum value
B. absolute maximum is at x =
; absolute minimum is -1 at x = -
C. absolute maximum is -1 at x = ; absolute minimum is
at x = -
D. absolute maximum is at x =
; absolute minimum is -1 at x = -
Solve the problem using the table below.In addition, options can be added to the base coverage including the following: identity theft/fraud protection-$20/year; sewer/sump pump backup protection-$75/year. Extended coverage endorsements beyond the maximum coverage amounts can also be added for specific personal property. Endorsements can be added for: jewelry, watches, and furs-$0.85/$100/year; camera equipment-$1.35/$100/year; computer equipment-$0.95/$100/year; fine art and collectibles-$1.10/$100/year; firearms and accessories-$1.45/ $100/year; and portable tools-$3.25/$100/year.A home with a replacement value of
src="https://sciemce.com/media/4/ppg__ttttt0617191018__f1q5g2.jpg" alt="" style="vertical-align: -4.0px;" /> is insured in a policy that contains an 80% coinsurance clause. The face value of the policy is If a fire causes damage valued at
find the amount of compensation to the owner by the insurance company.
A. $2400
B. $2667
C. $3375
D. $3000
Use the graph of the rational function f(x) to complete the statement.As x?+?, f(x)? .
A. -? B. 2 C. -2 D. +?
State the dual problem. Use y1, y2, y3 and y4 as the variables. Given: y1 ? 0, y2 ? 0, y3 ? 0, and y4Maximizez = x1 + 2x2 + 3x3subject to:6x1 + 3x2 + x3 ? 18 4x1 + 7x2 + 3x3 ? 35 x1 ? 0, x2 ? 0, x3 ? 0
A.
Minimize | w = 18y1 + 35y2 |
subject to: | 6y1 + 4y2 ? 1 |
y1 + 3y2 ? 3
B. Minimize w = 35y1 + 18y2
subject to: | 4y1 + 6y2 ? 1 |
3y1 + y2 ? 3
C. Minimize w = 35y1 + 18y2
subject to: | 4y1 + 6y2 ? 1 |
3y1 + y2 ? 3
D.
Minimize | w = 18y1 + 35y2 |
subject to: | 6y1 + 4y2 ? 1 |
y1 + 3y2 ? 3