Solve.An object that is vertically projected into the air has its height, in feet, above the ground given by s = -16t2 + v0t + s0,where s is the height, in feet, v0 is the initial velocity of the object, in feet per second, t is the time the object is in motion, in seconds, and s0 is the height, in feet, from which the object is projected. A ball is thrown straight up from a rooftop at an initial velocity of 82 feet per second from a height of 100 feet. The ball misses the rooftop on its way down and eventually strikes the ground below. How high above the ground will the ball be 4 seconds after being thrown?

Question

A. 154 ft
B. 666 ft
C. 172 ft
D. 684 ft

Answer 1

Answer: C