Find the unit tangent vector of the given curve.r(t) = (8 + 11t5)i + (6 + 2t5)j + (4 + 10t5)k

A. T(t) = i + j + k
B. T(t) = i + j + k
C. T(t) = 11i + 2j + 10k
D. T(t) = i + j + k

Answer: A

Mathematics

You might also like to view...

Solve the problem.A long distance phone company offers a promotional deal for the first month of service. They charge $15 basic fee for the month which includes 600 free minutes. Each additional minute costs $0.05. If Joe subscribes to this plan, how many minutes of calls can he make while keeping his total cost to no more than $42?

A. at most 540 min B. at most 1140 min C. at most 1040 min D. at most 1460 min

View

Mathematics

Find the center, transverse axis, vertices, foci, and asymptotes of the hyperbola.x2 - 16y2 - 8x - 64y - 64 = 0

A. center at (4, -2)
transverse axis is parallel to x-axis
vertices at (0, -2) and (8, -2)
foci at (4 - , -2) and (4 + , -2)
asymptotes of y + 2 = - (x - 4) and y + 2 = (x - 4)
B. center at (4, -2)
transverse axis is parallel to y-axis
vertices at (4, -6) and (4, 2)
foci at (4, -2 - ) and (4, -2 + )
asymptotes of y - 2 = - 4(x + 4) and y - 2 = 4(x + 4)
C. center at (-2, 4)
transverse axis is parallel to x-axis
vertices at (-6, 4) and (2, 4)
foci at (-2 - , 4) and (-2 + , 4)
asymptotes of y - 4 = - (x + 2) and y - 4 = (x + 2)
D. center at (4, -2)
transverse axis is parallel to x-axis
vertices at (3, -2) and (5, -2)
foci at (4 - , -2) and (4 + , -2)
asymptotes of y + 2 = - 4(x - 4) and y + 2 = 4(x - 4)