Solve the initial value problem for x as a function of t.(t + 2)  = x2 + 1 , t > -2 , x(4) = tan 1

A. x =  - 
B. x = tan [ ln - ln 6]
C. x = tan-1 [ ln - ln 6 + 1]
D. x = tan [ ln - ln 6 + 1]


Answer: D

Mathematics

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