Solve.A bullet is fired straight up into the air with a muzzle velocity of 236 meters per second, and after t seconds its height above the ground is h = 708 + 236t - 4.6t2 meters. Find an equivalent expression for the height of the bullet by factoring out a common factor.
A. h = 2(354 + 118t + 2.3t2)
B. h = 3(236 + 59t - 2.3t2)
C. h = 708(1 + 78.7t - 1.5t2)
D. h = 2(354 + 118t - 2.3t2)
Answer: D
Mathematics
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