Solve the problem.The position (in centimeters) of an object oscillating up and down at the end of a spring is given by 
at time t (in seconds). The value of A is the amplitude of the motion, k is a measure of the stiffness of the spring, and m is the mass of the object. Find the object's acceleration at time t.
A. a = - A sin 
cm/sec2
B. a = - A
sin 
cm/sec2
C. a = - 
sin 
cm/sec2
D. a = 
cos 
cm/sec2
Answer: C
You might also like to view...
Solve the problem.Find k such that the line kx + 15y = 4 is perpendicular to the line through (5, -8) and (-2, -4).
A. k = -26.25 B. k = -33.75 C. k = 26.25 D. k = 33.75
Find the area of the rhombus shown if WY = 30 cm.
Simplify the expression representing the derivative of a function.f'(x) = (4x4 - 3x3 + 6x - 5)(6x) + (x - 3)(6x2 - 6)
A. 24x5 - 18x4 + 6x3 - 36x2 - 36x + 18 B. 24x5 - 18x4 - 6x3 + 18x2 - 36x - 18 C. 24x5 - 18x4 + 6x3 + 18x2 - 36x + 18 D. 24x5 - 18x4 - 18x2 - 30x + 18
Convert the radical expression to its rational exponent form and then simplify. Assume that all variables represent positive numbers.
? 
A. x10/20 B. x20/10 C. x7/9 D. x33/20