Solve the equation using an integrating factor.
, t > 0
A. y = -t-4 + t3 + C
B. y = t-4 + t5
C. y = Ct-4 + t5
D. y = Ct4 + t5
Answer: C
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Solve the problem.A rescue cable attached to a helicopter weighs 2 lb/ft. A 160-lb man grabs the end of the rope and is pulled from the ocean into the helicopter. How much work is done in lifting the man if the helicopter is 30 ft above the water?
A. 4860 ft ? lb B. 5700 ft ? lb C. 1060 ft ? lb D. 6600 ft ? lb
Solve the problem.The position (in centimeters) of an object oscillating up and down at the end of a spring is given by at time t (in seconds). The value of A is the amplitude of the motion, k is a measure of the stiffness of the spring, and m is the mass of the object. Find the object's acceleration at time t.
A. a = - A sin
cm/sec2
B. a = cos
cm/sec2
C. a = - sin
cm/sec2
D. a = - A sin cm/sec2
Add or subtract.11 +
A. 16
B. 4
C. 17
D. 4
Solve the equation for the specified variable.Solve for b. A = h(B + b)
A. b =
B. b = 2A - Bh
C. b =
D. b =