Solve the problem.The average price for a box of crackers from 2000 to 2010 can be approximated by 
where x is the year. Evaluate P(2008) and round to the nearest hundredth. Interpret the result.
A. P(2008) = 2.69; the average price of a box of crackers in 2008 was $2.69.
B. P(2008) = 2.69; the average price of a box of crackers in 2008 was $2.69 more than in 2000.
C. P(2008) = 1.95; the average price of a box of crackers in 2008 was $1.95.
D. P(2008) = 2.78; the average price of a box of crackers in 2008 was $2.78.
Answer: A
You might also like to view...
Find the volume. Use ? ? 3.14. Round to the nearest tenth when necessary.a sphere with radius 13 in.
A. 707.5 in.3 B. 9198.1 in.3 C. 5173.9 in.3 D. 1149.8 in.3
Find the inverse of the one-to-one function.f(x) = -11x
A. f-1(x) = - 
x
B. f-1(x) = 
C. f-1(x) = 11x
D. f-1(x) = 
x
Graph the function f by starting with the graph of y = x2 and using transformations (shifting, compressing, stretching, and/or reflection).f(x) = -x2 + 6x 
A. 
B. 
C. 
D. 
Perform the indicated operation and, if possible, simplify.
+ 
A. 
B. 
C. 1
D. 