Which of the following statements is true for an adiabatic, reversible, steady-state compressor? Assume “the system” is defined as the fluid inside the compressor.

A. The efficiency of the reversible compressor can be calculated as a function of the inlet temperature (TC) and outlet temperature (TH).
B. The change in entropy for the system, the surroundings, and the universe are all zero.
C. The process described is impossible because heat must be rejected to a TC reservoir, which means the system cannot be adiabatic.
D. The process description results in -1 degrees of freedom, so the system is impossible.
E. None of the above is true.


A. Incorrect. This is true of a Carnot cycle where the temperatures are those of the heat sources and sinks, not material flows.
B. Correct. Because the system is reversible, no entropy is generated. Because the system is adiabatic, the Q/T term is 0. Steady-state means the time differential disappears. The entropy balance simplifies to Sin = Sout.
C. Incorrect. A compressor does not reject or accept heat (you are thinking of a heat engine). It DOES take an inlet stream at a certain temperature and specific entropy and produce an outlet stream with another, possibly different, temperature and specific entropy.
D. Incorrect. Degrees of freedom, as calculated using the Gibbs phase rule, refer to intensive properties. Here no intensive properties are specified, or even named.
E. Incorrect. One of these statements is true.

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The efficiency of a Carnot cycle operation between the same temperature limits as the diesel cycle above is nearest:

The pressure and temperature at the inlet to an ideal diesel cycle, with P-v diagram shown, are 100 kPa and 10ºC. It has a compression ratio of 18 and a cut-off ratio of 2. The maximum temperature in the cycle is 1400ºC. Assume constant
specific heats from Table below for all calculations.

A) 87%
B) 85%
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D) 81%

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