Venus has a planetary albedo of 0.8, and Mars has an albedo of 0.22. Using the answer to part (a), determine the effective radiating temperatures of these planets
What will be an ideal response?
Effective Radiating Temp:
Given: ?Te4 = S(1-A)/4
AVenus= 0.8
AMars = 0.22
Venus: Te=[(SVenus/4?)(1-AVenus)]1/4
Te=[(2642.8 W/m2 /4 (5.67 ? 10 –8 W/m2/K4)(1-0.8)]1/4
Venus Te = 219.7 K
Mars: Te=[(SMars/4?)(1-AMars)]1/4
Te=[(593.0 W/m2 /4 (5.67 ? 10 –8 W/m2/K4)(1-0.22)]1/4
Mars Te = 212.5 K
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